Time and Work Problems, solved Questions Online Quiz Test-Banking, SBI, SSC, All Exams

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Aptitude Time and Work Problems based Questions & Answer Quiz For All Exams

Qn1. Rahul, Aman and suresh can do a piece of work in 4,6 and 8 days respectively. In what will they altogether do it?
A.24/13 days
B.2 days
C.5/2 days
D.3 days

Answer-A.24/13 days
Rahul can do 1/4 times work in one day
Aman can do 1/6 times work in one day
and suresh can do 1/8 times work in one day
All three can do (1/4+1/6+1/8) times work in one day i.e. 13/24 units work
therefore, total time will be 24/13 days

Qn2. 19 men, working 6 hours a day can do a piece of work in 12 days. Find the number of days in which 38 men working 8 hours a day can do twice the work. Assume that 2 men of the first group do as much work in 1 hour as 3 men of the second group do in 1.5 hours.
A.20 days
B.22 days
C.24 days
D.20.25 days

Answer-D. 20.25 days
2 men of first group do as much work in 1 hours as 3 men of the second group in 1.5 hours
therefore,Ratio between efficiency of men of first group and men of 2nd group will be= 4.5:2
So we know, M1D1T1E1W2 = M2D2T2E2W1
D2= 19*6*12*4.5*2/38*8*2 = 20.25 days

Qn3. If 10 men and 6 boys can reap 23 acre in 4 days, and 3 men and 2 boys can reap 7 acre in 2 days, How many boys must assist 14 men in order that they may reap 45 acres in 6 days?
A. 4 boys
B. 2 boys
C. 5 boys
D. 6 boys

Answer-A.4 boys
Firstly we should find relationship b/w man and boys.
therefore, 10m+6b=23/4( in one day)...........(i)
3m+2b=7/2 ..............(ii)
Divide above equation with each other;
We find, 140m+84b=138m+92b
1m=4b....................(iii)
Then
5m+3b=10*4+6 boys=46 boys..................from (i)
now use M1D1W2=M2D2W1
M2= 46*45*4/23*5=60
therefore 60-14*4 = 4 boys must be assist with 14 men.

Qn4. A takes as much time as B and C together take to finish a job. A and B working together can finish the job in 20 days.C alone can do the same work in 30 days. in how many days can B do the same work?
A.100 days
B. 120 days
C. 110 days
D.none of these

Answer- B.120 days
Ratio b/w efficiency of A and B+C is 1:1.................eq.1
acc. to question A,B and C can do the work in 1 day= 1/20+1/30=5/60=1/12
therefore A,B and C can do a work in 12 days...............eq,2
according to eq.1
A or B+C will do whole work in 24 days.
therefore B will complete whole work in= 1/24-1/30=1/120 = 120 days

Qn5.A can do work in 50 days and B can do same work in 40 days. They work together for 5 days then B completes the remaining work. In how many days B will do the remaining work?
A.30 days
B.32 days
C.31 days
D.33 days

Answer-C.31 days
A and B both can do the work in 5 days= 5*(1/50+1/40)=9/200*5=9/40
rest of the work 1-9/40=31/40 will be done by B.
therefore B will do remaining work in 40*31/40 = 31 days.

Qn6. A and B can do a work in 45 and 40 days. They start working together and after some time A left and B finisher remaining work in 23 days. Find after how much time did A leave?
A.9 days
B.11 days
C.10 days
D.6 days

Answer-A.9 days
Work done by B in 23 days= 23/40
A+B work together 1-23/40= 17/40 work
A+B can do whole work in ( 1/45+1/40)=17/360 i.e 360/17 days
A+B will do 17/40 in =360/17*17/40 = 9 days

Qn7. A is twice as good as B. together they can finish the work in 10 days. n how many days will they do work separately?
A.15 days, 30 days
B.10 days, 15 days
C.20 days, 15 days
D.12 days, 15 days

Answer-A.15 days, 30 days
Ratio of efficiency between A:B= 2:1
Total work = 10*3=30 units
we know, time = work/efficiency
A can do work in 30/2 = 15 days
B can do work in 30/1 = 30 days

Qn8. A certain number of man can do a work in 70 days. if there are 10 more man it could be finished in 50 days. how many men are there?
A.30 Men
B.35 Men
C.20 Men
D.25 Men

Answer-D.25
We know M1D1=M2D2
let number of men =x
70x = 50*(x+10)
20x = 500
x= 25 men

Qn9. A is thrice as fast as B and able to complete the work in 24 days less than B. find the time in which both can do the work separately?
A.12 days,36 days
B.15 days, 39 days
C.10 days,34 days
D.none of these

Answer-A. 12 days,36 days
We can do it with ratio method;
according to question , ratio of efficiency= 3:1
ratio of time=1:3
so, difference b/w ratio=2 units
2 units =24 days
time taken by A i.e. 1 units = 12 days
time taken by B i.e. 3 units = 36 days

Qn10. There is sufficient food for 400 men for 32 days. after 28 days , 280 men leave the group. How long will the food last?
A.13 days
B.12 days
C.13 1/3 days
D.15 days

Answer-C.13 1/3 days
If no one had left the group then food had lasted for 4 days only.
Therefore, with 400 men food lasted for 4 days
with 120 men food will last for = 400*4/120 = 13 1/3 days

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1. UGC NET Paper 1 Series P Answer KeyAnswer Key Series PQ.NoAnsQ.NoAnsQ.No 13Q.No 263Q.No 21Q.No 272Q.No 33Q.No 284Q.No 41Q.No 294Q.No 53Q.No 303Q.No 61Q.No 312Q.No 74Q.No 323Q.No 83Q.No 334Q.No 94Q.No 344Q.No 101Q.No 354Q.No 113Q.No 362Q.No 121Q.No 374Q.No 131Q.No 382Q.No 144Q.No 393Q.No 154Q.No 40-Q.No 164Q.No 414Q.No 173Q.No 422Q.No 184Q.No 431Q.No 191Q.No 442Q.No 204Q.No 452Q.No 212Q.No 464Q.No 223Q.No 474Q.No 234Q.No 481Q.No 243Q.No 491Q.No 254Q.No 504
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UGC NET syllabus Paper 1 comprises of 10 Units. Each unit carries 5 Questions. It means the total number of questions will be 50. All questions are compulsory, so candidates have to attempt all the Questions. The Following 10 Units are given below: Teaching AptitudeResearch AptitudeReading ComprehensionCommunicationReasoning (Mathematics)Logical Rea…

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